A motor draws 50 A current from a 250 V, 50 Hz power supply and runs at 0.75 lagging power factor. What value of capacitor should be connected in parallel with it to increase the power factor to 0.90 lagging? (250 V, 50 Hz এর পাওয়ার সাপ্লাই হতে একটি মোটর 50 A কারেন্ট গ্রহণ করে 0.75 lagging পাওয়ার ফ্যাক্টরে চলে। পাওয়ার ফ্যাক্টর 0.90 lagging এ উন্নীত করতে হলে কত মানের ক্যাপাসিটর এর সাথে প্যারালালে সংযুক্ত করতে হবে?)

সুন্দরবন গ্যাস কোম্পানী লিমিটেড (SGCL) - Sub-Assistant Engineer (Electrical) (07-07-2017) ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

Created: 5 months ago | Updated: 5 months ago

Updated: 5 months ago

Ans :

$C = \frac{Q c}{ω V_{r m s}^{2}}$

$= \frac{P (\tan θ_{1} - \tan θ_{2})}{ω V_{r m s}^{2}}$

= $\frac{[250 \times 50 \times 0.75 \times \{\tan (\cos^{- 1} 0.75) - \tan (\cos^{- 1} 0.9)\}]}{(2 \times 3.1416 \times 50 \times 250^{2})}$

= 189.84 µF

5 months ago

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Question:
A motor draws 50 A current from a 250 V, 50 Hz power supply and runs at 0.75 lagging power factor. What value of capacitor should be connected in parallel with it to increase the power factor to 0.90 lagging? (250 V, 50 Hz এর পাওয়ার সাপ্লাই হতে একটি মোটর 50 A কারেন্ট গ্রহণ করে 0.75 lagging পাওয়ার ফ্যাক্টরে চলে। পাওয়ার ফ্যাক্টর 0.90 lagging এ উন্নীত করতে হলে কত মানের ক্যাপাসিটর এর সাথে প্যারালালে সংযুক্ত করতে হবে?)

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Find currents I and I₁ in the following circuit.

Created: 2 years ago | Updated: 8 months ago

Updated: 8 months ago

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৪৫ তম বিসিএস লিখিত ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

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Determine the Thevenin's equivalent circuit at terminal X-Y of the following circuit.

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Updated: 8 months ago

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৪৫ তম বিসিএস লিখিত ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

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Created: 2 years ago | Updated: 8 months ago

Updated: 8 months ago

Maximum Power Transfer Theorem :

In electrical engineering, the maximum power transfer theorem states that, to obtain maximum external power from a power source with internal resistance, the resistance of the load must equal the resistance of the source as viewed from its output terminals.

৪৫ তম বিসিএস লিখিত ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

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If the switch in the following circuit opens at t = 0, find v(t) for t≥ 0 and the initial energy stored in the capacitor.

Created: 2 years ago | Updated: 8 months ago

Updated: 8 months ago

For t<0, the switch is closed.

Capacitor acts as open to DC.

Voltage across the capacitor,

v(0^-)= {(12||4)×V}÷{(12||4)+6} = 8VFor t=0, the switch is opened,Voltage across the Capacitor cannot change instantaneously,So, v(0^-)= v(0) = 8VAt t>0, The capacitor is discharging.R_th= (12||4) = 3 ohmC= 1/6 FTime constant, Π = R_th×C = 0.5 So, v(t) = v(0)e^-t/Π = 8e^-t/0.5=8e^-2tV (Ans.)

৪৫ তম বিসিএস লিখিত ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

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Created: 2 years ago | Updated: 8 months ago

Updated: 8 months ago

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৪৫ তম বিসিএস লিখিত ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

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৪৫ তম বিসিএস লিখিত ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

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ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

Related Question

1
Find currents I and I₁ in the following circuit.

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ইলেকট্রিক্যাল এন্ড ইলেকট্রনিক্স ইঞ্জিনিয়ারিং (EEE)

Related Question

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4 If the switch in the following circuit opens at t = 0, find v(t) for t≥ 0 and the initial energy stored in the capacitor.

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